Creating a random matrix with conditions without using iteration

Is it possible to make a matrix using rand where all values less than a certain value, such as 5, are replaced by 0? Without any iteration by the way.

I know you can just do:

A=10*rand(5,5); 
A=(A(:,:)>5).*A(:,:)

But this iterates off the previous declaration.

[Gregory Shoemake]

I'm beginning to wonder if maybe I'm just misunderstanding the meaning of iteration. Pretty new to MatLab so please excuse if this is common knowledge.

Answer 1

[KSSV]

A=10*rand(5,5); 
A(A<5) = 0 ;

Answer 2

[Jan]

This is fine:

A = (A>5) .* A

There is not reason to avoid this. Using 2 lines instead of one is not a drawback.

An "iteration" means a loop usually. So you code does not contain an iteration (if we ignore that Matlab uses loops internally to process the elements of the array).

[Gregory Shoemake]

Thank you! really cleared things up. Also can I ask how I might complete the same task using iteration?

Answer 3

[Jos (10584)]

A = [1 5 3 2 4]
A(A>3) = 0 % all at once, the way to go!!

B = [1 5 3 2 4]
for k=1:numel(B), % iteration over each element of B
  if B(k) > 3, 
     B(k) = 0 ; 
  end ; 
end