Delete rows from Cell Array

I have a cell array as seen in the image. I want to delete the rows of the cell array where the first column is less than 3. Thanks.

Answer 1

[Walter Roberson]

mask = cell2mat(YourCell(:,1)) < 3;
YourCell(mask, :) = [];

[Tyler Smith]

Works great! Thanks.

Answer 2

[Hedayat]

If you want to delete more than one rows of cell you can ...

a= cell(5,5)

a =

5×5 cell array

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

a([2,3],:)=[]

a =

3×5 cell array

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}

Answer 3

[Asad (Mehrzad) Khoddam]

a is the cell array

b=find(cellfun(@(x) size(x,1)<3,a)==1);
while ~isempty(b)
    a(b(1))=[];
    b=b-1;
    b(1)=[];
end

[Walter Roberson]

No, this checks for vectors less than 3 elements anywhere in the cell array.

The == 1 is redundant because the places that satisfy <3 will already return 1 and the other places will return 0 and find() automatically checks for non-zero. The code there is sort of like

find((x < 3) == true)

when you could just use

find(x < 3)