Help aligning two vectors with one centred on zero.

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Jason
Jason el 25 de Oct. de 2016
Comentada: Chaya N el 25 de Oct. de 2016
I have a set of x values:
x1=-31, -15.5, 0, 14.9,30.2
I know that the separation should be 15 (=pitch) so I want to plot x1 against xreal then do a fit and look at the largest deviation.
I can create:
xreal=Pitch*((1:numel(x1)));
But I can't figure out how to align them AROUND 0,e.g
xreal = -30, -15, 0 , 15, 30
then I can easily plot x1 against xreal and linearly fit.

Respuesta aceptada

LauraLee Austin
LauraLee Austin el 25 de Oct. de 2016
How about this, it should allow the location of 0 in x1 to change and the number of values in set x1 to be variable as well. if true
x1 = [-31, -15.5, 0, 14.9,30.2];
Pitch = 15;
idx = find(x1==0);
numel(x1)
xreal=(Pitch*(1-idx)):Pitch:(Pitch*(numel(x1)-idx));

Más respuestas (2)

Chaya N
Chaya N el 25 de Oct. de 2016
Editada: Chaya N el 25 de Oct. de 2016
xreal=Pitch*((1:numel(x1)) - ceil(numel(x1)/2))
  2 comentarios
Jason
Jason el 25 de Oct. de 2016
doesn't this assume that the x1 values are symmetrical around 0. although shown in the example, this may not always be the case.
Chaya N
Chaya N el 25 de Oct. de 2016
"...align them AROUND 0"
Exactly as asked!

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Matt J
Matt J el 25 de Oct. de 2016
xreal=xreal-mean(xreal);
  3 comentarios
Matt J
Matt J el 25 de Oct. de 2016
Editada: Matt J el 25 de Oct. de 2016
The mean of xreal would still be at zero. That is the only interpretation of the requirement "centered AROUND 0" that we can intuit from your post.
Jason
Jason el 25 de Oct. de 2016
Yes sorry, I only thought of it after you had answered.

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