How to label a matrix

I have following code, I wanna give label to a matrix with 1 or -1 based on the type. I know it will give an error "Subscript indices must either be real positive integers or logicals." But I don't have any idea how to fix it.
if jenis == 1
T(feature)= 1;
else
T(feature)= -1;
end
Please help me anyone. Thank you.

2 comentarios

dpb
dpb el 16 de Nov. de 2016
If you mean feature is supposed to be -1|1, then no, "You can't do that!". Scale to use [1|2] instead if insist on using array indices as the segregating method.
Rather, I'd suggest keeping a corollary variable instead; it could be categorical rather than numeric. The table might be useful here... <table>
Image Analyst
Image Analyst el 16 de Nov. de 2016
What is jenis? A scalar? Your matrix?
What is feature? It must be natural integers starting with 1, like 1,2,3,4,5,....etc.
What is the name of your matrix? jenis? Or T? Or something else???

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Respuestas (1)

Jan
Jan el 16 de Nov. de 2016

0 votos

What about using a struct?
T.data = rand(5);
T.feature = -1; % or +1

2 comentarios

Tuffahatul Ummah
Tuffahatul Ummah el 16 de Nov. de 2016
Editada: Tuffahatul Ummah el 16 de Nov. de 2016
Sorry, but the toolbox I use can't receive a struct data.
dpb
dpb el 16 de Nov. de 2016
Well, it would certainly help to see an actual illustration of how you think you need to use this "feature"...otherwise we're only able to say "here's a rock" and you keep saying, "no, not that rock!" (much like a DOE program manager I worked for many, many years ago until I finally broke him :) ).

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