Indexing into a multidemesional array using a multidimensional array

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This question seems similar to a previously answered question, but I'm not sure if the answer there applies to my problem.
I have an array, X, which has dimensions k by m by n and I have another array, Y, with indices for the first dimension k, which has dimensions m by n. I want to create an output matrix of m by n of each value of X in the k dimension where the index in that k dimension corresponds to the value in Y for each value of m and n.
I know that is a bit confusing, but in essence I want to achieve the following code via clever application of indexing, rather than using nested for loops.
m = size(X,2);
n = size(X,3);
for m_count = 1:length(m)
for n_count = 1:length(n)
output(m_count,n_count) = X(Y(m_count,n_count),m_count,n_count)
end
end

Respuesta aceptada

Guillaume
Guillaume el 18 de Nov. de 2016
I think it should rather be:
[rows, columns] = ndgrid(1:size(Y, 1), 1:size(Y, 2));
output = X(sub2ind(size(X), Y, rows, columns))
  2 comentarios
Kevin McAughey
Kevin McAughey el 18 de Nov. de 2016
This seems to work perfectly, now I'll just have to look through it so that I can understand why!
Guillaume
Guillaume el 18 de Nov. de 2016
rows and columns are just two matrices corresponding to the row and column indices of the corresponding elements of Y.
sub2ind converts these three coordinate matrices into a single linear index which can be used to index X.

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Jan
Jan el 18 de Nov. de 2016
Editada: Jan el 18 de Nov. de 2016
Try this:
output = X(sub2ind(size(X), Y(:), 1:size(x,2), 1:size(x,3))
  1 comentario
Kevin McAughey
Kevin McAughey el 18 de Nov. de 2016
When I tried this it threw the following error:
Error using sub2ind (line 51)
The subscript vectors must all be of the same size.

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