additional findchangepts function output
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Michal
el 23 de Nov. de 2016
Comentada: Greg Dionne
el 18 de En. de 2017
I have two questions regarding function "findchangepts" (DSP Toolbox):
1. How to effectively create additional output vector "x_hat" from standard output "ipt" of the "findchangepts" function at the same sample grid as input data "x". The "x_hat" vector corresponds to function which is piecewise constant or linear approximation of the input "x" signal with jumps at detected change points "ipt" and is produced only as graphics output by "findchangepts" in case of no output variables (see internal function "cpplot" at "findchangepts.m" source code file).
2. Any idea how to choose the input parameters of the "findchangepts" function to restrict output change points only for jump steps values less than some threshold value?
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Greg Dionne
el 23 de Nov. de 2016
#1 Maybe something like:
function y = fitchangepts(x, icp, statistic)
y = nan(size(x));
K = length(icp);
nseg = K+1;
istart = [1; icp(:)];
istop = [icp(:)-1; length(x)];
if strcmp(statistic,'mean') || strcmp(statistic,'std')
for s=1:nseg
ix = (istart(s):istop(s))';
y(ix) = mean(x(ix));
end
elseif strcmp(statistic,'rms')
for s=1:nseg
ix = (istart(s):istop(s))';
y(ix) = rms(x(ix));
end
else % linear
for s=1:nseg
ix = (istart(s):istop(s))';
y(ix) = polyval(polyfit(ix,x(ix),1),ix);
end
end
Test it:
load engineRPM.mat
plot(fitchangepts(x,findchangepts(x,'Statistic','linear','MinThreshold',var(x)/2),'linear'))
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Greg Dionne
el 23 de Nov. de 2016
#2 You can get close to this by running FINDCHANGEPTS once with a given threshold, finding all segments that are too long, and re-running on each of these with lower thresholds.
You'll probably want to explain the motivation behind the request though, so the solution works for you.
1 comentario
Greg Dionne
el 28 de Nov. de 2016
I don't think I have a good answer to this. The 'mean' option works by performing a sum residual square error, introducing a constant penalty for each break. So if we have a signal with a small shift in mean over a large number of samples, the sum of the residuals would eventually swamp the computation and force a break (no matter how small the shift). This doesn't seem like what you want. The only other option which takes mean into account is the 'std' option; if your noise is distributed uniformly over all segments, maybe that could work(?). No promises of course, but if you share your data I can try to come up with something practical.
9 comentarios
Greg Dionne
el 18 de En. de 2017
The main problem occurs when the slope of the trend is steep and the quantized levels are moving in the opposing sense. Then it becomes difficult to extract.
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