Borrar filtros
Borrar filtros

how can i patch a circle in the origin of the axis?

7 visualizaciones (últimos 30 días)
juan diego villada
juan diego villada el 7 de Dic. de 2016
Comentada: Iddo Weiner el 8 de Dic. de 2016
wich cordinates can i use
  3 comentarios
juan diego villada
juan diego villada el 8 de Dic. de 2016
thanks Iddo , that was what i needed
Iddo Weiner
Iddo Weiner el 8 de Dic. de 2016
Glad to help..
If you could accept an answer it would be of help for the next people who read this question.. My answer is given below, and KSSV's answer is essentially the same so - whichever one, it doesn't really matter...
Good luck

Iniciar sesión para comentar.

Respuestas (2)

KSSV
KSSV el 8 de Dic. de 2016
clc; clear all ;
R = 1 ;
th = linspace(0,2*pi) ;
x = R*cos(th) ;
y = R*sin(th) ;
patch(x,y,'r') ;
axis equal

Iddo Weiner
Iddo Weiner el 8 de Dic. de 2016
See my initial answer, I posted it as a comment by mistake:
rad = 10; %this is the radius (change it if you like)
angle = 0:0.001:2*pi; % a full circle range
x_cord = rad*cos(angle);
y_cord = rad*sin(angle);
plot(x_cord, y_cord);
hold on
plot(xlim,[0 0])
plot([0 0],ylim)
hold off

Categorías

Más información sobre 2-D and 3-D Plots en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by