How to plot a piecewise function?

3 comentarios

Roger Stafford
Roger Stafford el 21 de Dic. de 2016
The problem with your code is that when you apply an ‘if’ to an entire vector, as you have done with “if x<0”, it is not regarded as true by matlab unless all elements of that vector are true, and that of course is not the case, so the ‘if’ will fail. The same hold true with your other two if’s - they will all fail and y is never set.
Stephen23
Stephen23 el 25 de Dic. de 2020
Original question asked by Alexandros Dhimas on 20th December 2016 retrieved from Google Cache:
How to plot a polyclonal expression using if statement?
Hello, I' ve got a polyclonal function to plot (using if statement) as shown on this picture:
for -5<x<30.
My thougth on the solution was:
x=linspace(-5,30,1000);
if x<0
y=10*x.^0;
else if x>=0 & x<9
y=10*x+10;
else if 9<=x
y=15*sqrt(4*x)+10;
end
end
end
plot(x,y)
But i get this on the command window "Error using plot A numeric or double convertible argument is expected"
I can't find any mistakes on my code.
Walter Roberson
Walter Roberson el 25 de Dic. de 2020
This is not a Duplicate.

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 Respuesta aceptada

Alexandros Dhimas
Alexandros Dhimas el 21 de Dic. de 2016
Editada: Alexandros Dhimas el 21 de Dic. de 2016
Solution usin if statement:
x=linspace(-5,30,1000);
for i=1:1000
if x(i)<0
y(i)=10;
elseif x(i)>=0 & x(i)<9
y(i)=10*x(i)+10;
else
y(i)=15*sqrt(4*x(i))+10;
end
end
plot(x,y)

Más respuestas (2)

Roger Stafford
Roger Stafford el 21 de Dic. de 2016
If you only want to plot the function, do this:
x1 = linspace(-5,0,50); y1 = 10*ones(1,50);
x2 = linspace(0,9,90); y2 = 10*x2+10;
x3 = linspace(9,30,210); y3 = 15*sqrt(4*x3)+10;
plot([x1,x2,x3],[y1,y2,y3])
Another way:
x = linspace(-5,30,400);
y = (x<0)*10+(x>=0&x<9).*(10*x+10)+(x>=9).*(15*sqrt(4*abs(x))+10);
plot(x,y)

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