Direction Cosine Matrix using left-handed coordinate system?
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Tilman
el 29 de Dic. de 2016
Hi, is there any reason why angle2dcm uses a left-handed coordinate system?
angle2dcm(pi/6, 0, 0, 'XYZ') =
1.0000 0 0
0 0.8660 0.5000
0 -0.5000 0.8660
When I multiply this with a vector in z-direction I can see that the function does not follow the right hand rule for rotation. The function rotx however rotates the other way round. I'm using a simulink 6dof model block. Matlab help says that the dcm which is one of the block outputs gives me the transformation from inertial to body and the used system is a right-handed system. Does anyone know why Matlab is doing this?
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John D'Errico
el 29 de Dic. de 2016
It is always nice if you tell people where (which toolbox) a function comes from. Don't force people to search for it, as that just makes them work to answer your question. You want to make it as easy as possible to get an answer.
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Matt J
el 29 de Dic. de 2016
Editada: Matt J
el 29 de Dic. de 2016
I can't be sure, but some Matlab Toolboxes (e.g., Image Processing) like to represent coordinates as row vectors instead of column vectors. This means they need to perform transformations by right-multiplying row vectors with transformation matrices instead of left-multiplying. If this is the convention of the Aerospace Toolbox as well, the result
R=angle2dcm(pi/6, 0, 0, 'XYZ')
is perfectly consistent with a right handed system. You are simply meant to be executing the transform as [0,0,1]*R instead of R*[0;0;1].
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