compare between vector and cell

Dear all, I have one vector (b) and one cell (a) as shown below: How I know how many times each number in vector b repeat it in a.

 a=[{[1,9,79,3]  [2,29,16,7,3] 3 [4,74,3] [5,73,79,3] [6,56,3] [7,3]}]
 b=[ 79 3 74 10];

the expect result should be;

 result= [ 2 7 1 0];

Thanks alot

[Stephen23]

Question is continued here:

https://www.mathworks.com/matlabcentral/answers/318671-take-part-of-cell-depend-on-vector

Answer 1

[KSSV]

a=[{[1,9,79,3]  [2,29,16,7,3] 3 [4,74,3] [5,73,79,3] [6,56,3] [7,3]}] ;
b=[ 79 3 74 10]; 
result= [ 2 7 1 0];
a_mat = cell2mat(a) ;
for i = 1:length(b)
    result(i) = length(find(a_mat==b(i)))
end

[skysky2000]

That perfect KSSV, I appreciate it .

Thankssss alot

Answer 2

[Stephen23]

A much simpler solution:

>> a = {[1,9,79,3],[2,29,16,7,3],3,[4,74,3],[5,73,79,3],[6,56,3],[7,3]};
>> b = [79,3,74,10];
>> sum(bsxfun(@eq,[a{:}],b(:)),2)
ans =
     2
     7
     1
     0

[skysky2000]

Thanks Stephen, What about the second question?

Answer 3

[skysky2000]

Dear KSSV, another question. Can I take the cell that number repeat it on it with same loop. like for example:

 a=[{[1,9,79,3]  [2,29,16,7,3] 3 [4,74,3] [5,73,79,3] [6,56,3] [7,3]}] ;
 b=[ 79 3 74 10]; 
 result= [ 2 7 1 0];

cell-part 79= [{[1,9,79,3] [5,73,79,3]}]
cell_part 3 = [{[1,9,79,3]  [2,29,16,7,3] 3 [4,74,3] [5,73,79,3] [6,56,3] [7,3]}];
cell_part 74 = {[4,74,3]}
cell_part 10 = {0};

thankss

[Stephen23]

@skysky2000: that is not a good idea: naming variables dynamically will make your code slow, buggy, and hard to follow. Read this to know why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

A much better solution is to learn to use indexing, which is fast and efficient.