Borrar filtros
Borrar filtros

How to add row values in matrix using a loop?

1 visualización (últimos 30 días)
Yuli Hartini
Yuli Hartini el 2 de En. de 2017
Comentada: Walter Roberson el 3 de En. de 2017
I have matrix A
A = [ 1 1 2 0.1;
2 2 3 0.02;
3 3 4 0.05;
4 4 5 0.3;
5 2 6 0.5;
6 2 7 0.4;
7 7 8 0.2;
8 3 9 0.9;
9 4 10 1.3
];
I want to add row values like that using a loop..
X1 = A(1,4)
X2 = A(1,4)+A(2,4)
X3 = A(1,4)+A(2,4)+A(3,4)
X4 = A(1,4)+A(2,4)+A(3,4)+A(4,4)
X5 = A(1,4)+A(2,4)+A(5,4)
X6 = A(1,4)+A(2,4)+A(6,4)
X7 = A(1,4)+A(2,4)+A(6,4)+A(7,4)
X8 = A(1,4)+A(2,4)+A(3,4)+A(8,4)
X9 = A(1,4)+A(2,4)+A(3,4)+A(4,4)+A(4,9)
B= [ X1;
X2;
X3;
X4;
X5;
X6;
X7;
X8;
X9;
];
How can I do that? Any tips?
Many Thanks in advance
  5 comentarios
Yuli Hartini
Yuli Hartini el 3 de En. de 2017
How about this: Number will follow the lines of A (:, 1), and will cease in A (:, 2). When A(:,2)=(A(:,3)+1)
How can I do that?
Walter Roberson
Walter Roberson el 3 de En. de 2017
None of your examples have A(:,2)=(A(:,3)+1) . In some cases A(:,2)=(A(:,3)-1) .
Your proposed rule is not clear on what to do when the relationship between those two columns does not hold.

Iniciar sesión para comentar.

Respuestas (0)

Categorías

Más información sobre Creating and Concatenating Matrices en Help Center y File Exchange.

Productos

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by