Q=0.25;
L=5;
a=1-cos(2*pi*D1/fn);
x=(pi*D1)/(fn*L)*sin(2*pi*D1/fn);
y=cos(2*pi*D1/fn)*((4*Q/pi*fn)+((pi^2*D1/fn^2*L)*(0.5-D1))-1);
z=(pi^2*D1/fn^2*L)*(0.5-D1);
m=4*Q/pi*fn;
deno=1+x+y+z+m;
Gdc1=a/deno;
Hi I want to plot a surface of Gdc where D1=0.1:0.1:0.5 and fn=0.5:0.1:1.5
How can I do it?

 Respuesta aceptada

Walter Roberson
Walter Roberson el 25 de En. de 2017

0 votos

Q = 0.25;
L = 5;
[D1, fn] = ndgrid(0.1:0.1:0.5, 0.5:0.1:1.5);
D1_fn = D1./fn; %optimization
a = 1 - cos(2*pi*D1_fn);
x = (pi*D1) ./ (fn*L) .* sin(2*pi*D1_fn);
y = cos(2*pi*D1_fn) .* ((4*Q/pi*fn) + ((pi^2*D1_fn./fn*L) .* (0.5-D1)) - 1);
z = (pi^2*D1_fn./fn*L) .* (0.5-D1);
m = 4*Q/pi * fn;
deno = 1+x+y+z+m;
Gdc1 = a ./ deno;
surf(D1, fn, Gdc1, 'edgecolor', 'none')

3 comentarios

safi58
safi58 el 25 de En. de 2017
Hi Walter, is it possible to do plotting like this figure?
Walter Roberson
Walter Roberson el 25 de En. de 2017
surf(D1, fn, Gdc1)
Your plot is course because 0.1:0.1:0.5 is course. You should probably use a finer resolution. For example,
N = 20;
[D1, fn] = ndgrid(linspace(0.1,0.5,N), linspace(0.5,1.5,N));
safi58
safi58 el 26 de En. de 2017
thank you so much

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