Matlab workers in Parloop are not using the path order

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Leandro
Leandro el 25 de En. de 2017
Movida: Walter Roberson el 29 de En. de 2026 a las 21:40
Hello, I'm using this code
parfor k=1:10
[..]=pca(..)
end
I have 2 definitions of pca (the matlab package and another package). I've set the search path to use the matlab package by default, but inside the parloop the other function is used instead. I didn't found a way to arrange this without removing the other package. Thanks
  4 comentarios
Adam
Adam el 2 de Feb. de 2018
I would have thought if one of them was in a package that you would have to specify it with the package name prepended, which would remove the ambiguity anyway.
Xingwang Yong
Xingwang Yong el 29 de En. de 2026 a las 19:54
Movida: Walter Roberson el 29 de En. de 2026 a las 21:40
I am using R2024b, still have the problem.

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Edric Ellis
Edric Ellis el 26 de En. de 2017
This appears to be a problem with the automatic path mirroring that is used when setting up a parallel pool. Things work correctly if you modify the client MATLAB path only after creating the parallel pool.
  2 comentarios
Leandro
Leandro el 26 de En. de 2017
Thank you! Indeed a strage bug, becouse you can set path priorities in the IDE, so it should be mirrored in the same way.
Thomas Pfau
Thomas Pfau el 2 de Feb. de 2018
But which path is matlab using then? I have a very similar situation:
2 Toolboxes, both have the same function name. In our code we dynamically change the path depending on which of the toolboxes is required. However, as soon as there is a parfor loop, we are in trouble, as the path seems to be ignoring anything we do before.
  • Changing the path before the pool is created -> No Effect
  • Changing the path after the pool is created -> No Effect.
The only thing I see is to change the path in the parfor loop, but this (at least in our case) would create an overhead that would make parfor pointless.
I'm really wondering, whether there is any way to manipulate the path of a cluster or how the cluster determines its path.

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