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split a row into 2 rows

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chocho
chocho el 16 de Feb. de 2017
Comentada: chocho el 22 de Feb. de 2017
cg00008493 0.987979722052904 "COX8C;KIAA1409" 14 93813777 0.986128428295584 "COX8C;KIAA1409" 14 93813777
cg00031162 0.378288688845672 "TNFSF12;TNFSF12-TNFSF13" 17 7453377 0.362510745266914 "TNFSF12;TNFSF12-TNFSF13" 17 7453377
here are 2 lines and each line have 8 columns, i want to split each line have 2 sets like "COX8C;KIAA1409" into 2 rows and delete the duplicated columns output should be like this:
cg00008493 0.987979722052904 COX8C 0.986128428295584
cg00008493 0.987979722052904 KIAA1409 0.986128428295584
cg00031162 0.378288688845672 "TNFSF12 0.362510745266914
cg00031162 0.378288688845672 TNFSF12-TNFSF13 0.362510745266914
fid = fopen('COADREAD_methylation.txt','r');
data={};
while ~feof(fid)
l=fgetl(fid);
if isempty(strfind(l,'NA')), data=[data;{l}]; end
a = reshape(l, ',','""', [])';
end
fid=fclose(fid);
Note: I used NA to remove the lines which have NA

Respuesta aceptada

Stephen23
Stephen23 el 16 de Feb. de 2017
Editada: Stephen23 el 17 de Feb. de 2017
opt = {'CollectOutput',true};
inp = '%s%s%q%*d%*d%s%*q%*d%*d';
out = '%s\t%s\t%s\t%s\n';
f1d = fopen('temp1.txt','rt'); % the original file
f2d = fopen('temp2.txt','wt'); % the new file
while ~feof(f1d)
C = textscan(f1d,inp,1,opt{:});
C = [C{:}];
D = regexp(C{3},';','split');
for k = 1:numel(D)
fprintf(f2d,out,C{1:2},D{k},C{4});
end
end
fclose(f1d);
fclose(f2d);
Produces this output file:
cg00008493 0.987979722052904 COX8C 0.986128428295584
cg00008493 0.987979722052904 KIAA1409 0.986128428295584
cg00031162 0.378288688845672 TNFSF12 0.362510745266914
cg00031162 0.378288688845672 TNFSF12-TNFSF13 0.362510745266914
Tested on this input file:
  18 comentarios
Stephen23
Stephen23 el 22 de Feb. de 2017
If textscan has an empty output then you probably need to check the format string.
chocho
chocho el 22 de Feb. de 2017
could you tell me how to present the format of this line? cg00000292 0.511852232819811 ATP2A1 0.787687855895422 0.51208122605745 0.599610258157912 0.568034757766559

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