Integration with negative support

Hi, I would like to integrate something like this

   z=@(x) x<0;
   integral(exppdf(z,10),-0.5, 0.5);

Any help will be useful. Thanks

Answer 1

[Rik]

You are aware that you are not creating a bound, but a function that says that z is either 1 or 0?

And that there is a vital difference between integrate() and integral()?

Anyway, I copied out the function that exppdf calculates from its help, which resulted in the code below:

mu=10;
z=@(x) (1/mu)*exp(-x/mu);
integral(z,-0.5, 0.5);

[Nikolas]

Thanks for your answer. Is it possible to take only x<0?

[Rik]

Sure, but not if you are integrating for x from -0.5 to 0.5

integral(z,-0.5, 0);

[Nikolas]

Thank you once again for your post. What about if i use exppdf, which is a built in function in MATLAB which returns 0 if x<0, can I use it? Then I think if you take the integral

integral(z,0,0.5)

should return zero. I want to use this function.

[Rik]

Why do you want to use this function? And if you use exppdf as an input, the integral for 0 to 0.5 should not be 0. There is another thing that may be what you mean:

z2=@(x) exppdf(-x,mu);%turn positive x into negative and vice versa

This will return 0 for integral(z2,0,0.5)