Borrar filtros
Borrar filtros

ODE function in a loop

1 visualización (últimos 30 días)
Physics
Physics el 2 de Mzo. de 2017
Comentada: Walter Roberson el 4 de Mzo. de 2017
I have a function of x and t, and am creating a loop to find the average x/t for every U. I have successfully used this method before, however my x values are zero every time.
My function is:
function dx=myfunction(t,x,U)
de=24.35;
dd=294.5.*10^(-9);
hbar=6.5.*10^(-16);%
lambda=20*d;
k=(2.*pi)/(lambda);
v=2.5.*10^(-3);
dx=zeros(3,1);
dx(1)=((de)/(2.*hbar.*v.*k)).*sin(x(2));
dx(2)=(dd.*U)./(hbar.*2*v).*(cos(((pi.*x(1))/10)-(t)));
end
In the loop:
dU=1;
U=0:dU:200;%
tspan=[1 30];
vx=zeros(size(U));
for j=1:length(U)
[t,x]=ode45(@(t,x) myfunction(t,x,U(j)),tspan,[0 0 0]);
vx(j)=(sum((x(:,1))./(t))./(length(t));
end
Any ideas as to why the changing of U gives x a value of 0 would be useful.
Thanks in advance.
  3 comentarios
Physics
Physics el 2 de Mzo. de 2017
Editada: Physics el 2 de Mzo. de 2017
I have edited the constants and names. Changed it for ease.
Jan
Jan el 3 de Mzo. de 2017
Note: While dd=294.5.*10^(-9) is an exüpensive power operation, dd=294.5e-9 is a cheap constant.

Iniciar sesión para comentar.

Respuestas (1)

Jan
Jan el 3 de Mzo. de 2017
The code will not run at all, because the number of parenthesis in
vx(j) = (sum((x(:,1))./(t))./(length(t));
is wrong. I guess you want:
vx(j) = sum(x(:,1) ./ t) ./ length(t);
It is useful to use additional parenthesis, if it improves the readability of the code, but here this was an overdoing.
If this is fixed, runnign your code fails in the line:
lambda=20*d;
due to an undefined variable "d".
Finally all I can suggest to use the debugger to examine, what's going on. Set a breakpoint in your code and step through the program line by line. This helps to understand, where which values are defined. Please post the running code afterwards, if you still have problems.
  2 comentarios
Physics
Physics el 3 de Mzo. de 2017
Thanks so much for taking the time to look at this.
These issues again are from my editing to create this post - they would clearly show as errors when running!
I was getting 0 values from the size of my range, as a solution for your interest.
Thanks again!
Walter Roberson
Walter Roberson el 4 de Mzo. de 2017
If you are still having difficulty, please post corrected code.

Iniciar sesión para comentar.

Categorías

Más información sobre Programming en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by