Inserting Zeros in a Matrix
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Hi
Is there a way of inserting zeros in a data-matrix of 3x1(say). Only thing the zeros need to be inserted in those positions outside the data-matrix. So you would get a 10x1 matrix of zeros and datavalues.
For example,
DataCol = [x1;x2;x3] % Data column
NewDataCol = [0;0;0;0;0;x1;x2;x3;0;0] % New Data Column
The length of the DataCol changes each time.
Is there an easy way to insert the necessary zeros depending on the length of the data column?
Thanks
Ferd
3 comentarios
Oleg Komarov
el 20 de Mzo. de 2012
Yes, but you have to tell us on which position to start inserting DataCol each time into the colum of zeros.
Or phrased differently, what's the rule that decides how many zeros above and how many below.
Respuesta aceptada
Dr. Seis
el 20 de Mzo. de 2012
preZeros = 5;
postZeros = 2;
DataCol = rand(3,1);
%if really column vector
NewDataCol = zeros(length(DataCol)+preZeros+postZeros,1);
NewDataCol(preZeros+(1:length(DataCol)),1) = DataCol;
Más respuestas (2)
Daniel Shub
el 20 de Mzo. de 2012
Based on the additional information in your comment, you have x (160x1) and you want a function that will take in some offset b (0 <= b <= 200) and x and then create a matrix y (360x1) such that x(i) = y(i+b) for 1 <= i <= 160?
Without any error checking
f = @(b, x)([zeros(b, 1); x; zeros(200-b, 1)]);
NewDataCol = f(0, DataCol);
NewDataCol = f(200, DataCol);
4 comentarios
Daniel Shub
el 20 de Mzo. de 2012
Also, the best way to show appreciation on the answers is by up voting.
Geoff
el 20 de Mzo. de 2012
How about this:
startRow = 6;
NewDataCol = zeros(10,1);
NewDataCol(startRow-1 + (1:numel(DataCol))) = DataCol;
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