How to Change Values of a Field by an Indexing Array?

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Rightia Rollmann
Rightia Rollmann el 12 de Mzo. de 2017
Editada: Jan el 13 de Mzo. de 2017
Here’s my initial struct:
A(1).B.C = 'a';
A(2).B.C = 'b';
A(3).B.C = 'a';
A(4).B.C = 'a';
I want to change the values of C based on values of Values and indexes of IndexingArray:
Values = {'a', 'b'}
IndexingArray = [1 1 0 1];
So, my struct will be:
A(1).B.C = 'b';
A(2).B.C = 'b';
A(3).B.C = 'a';
A(4).B.C = 'b';
What is the solution?

Respuesta aceptada

Chad Greene
Chad Greene el 12 de Mzo. de 2017
You could change each element individually via loop. But make sure you add 1 to the indexing array values because Matlab starts indexing at 1, not 0.
for k = 1:length(A)
A(k).B.C = Values(IndexingArray(k)+1);
end
  3 comentarios
Jan
Jan el 13 de Mzo. de 2017
Editada: Jan el 13 de Mzo. de 2017
@Rightia Rollmann: The nested struct is a complicated method to represent data. In consequence the method to access the values is not trivial anymore. This loop is efficient and compact. (+1)
Assumingly a typo:
A(k).B.C = Values{IndexingArray(k)+1}; % Curly braces
Chad Greene
Chad Greene el 13 de Mzo. de 2017
Ah, yes, curly braces. Thanks for catching that Jan!

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