I want to access an excel file with 500 by 2 matrix and check the connected nodes(bidirectional) in that matrix and the output will be a matrix with 1 represent connection otherwise 0.When I run this code,the error is"Maximum variable size exceeded"

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clc;
A = csvread('twitnet');
numnode = max(A(:));
adj = zeros(numnode,numnode);
fromlist = A(:,1);
tolist = A(:,2);
fromtoidx = sub2ind([numnode,numnode], fromlist, tolist);
adj(fromtoidx) = 1;
tofromidx = sub2ind([numnode,numnode], tolist, fromlist);
adj(tofromidx) = 1;
  5 comentarios
SUNANNA S S
SUNANNA S S el 24 de Mzo. de 2017
Sir, For eg: A group has six nodes, i.e., a, b, c, d, e, and f .The links of the nodes are ab, ac, ad, ae, ba, bc, bd, bf, be,cd, cf, da, dc, df, ea, ed, ef, and fe. The unique nodes of both followees and followers are a, b, c, d, e, and f . So, I want a 6 by 6 matrix x in which, a is connected to b, c, d, and e; therefore, x12 = x13 = x14 = x15 = 1. By contrast, a is not connected to a and f, therefore x11 = x16 = 0. All the other cells are assigned values using the same method. Thanks

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Respuestas (1)

Jan
Jan el 13 de Mzo. de 2017
Editada: Jan el 13 de Mzo. de 2017
The values in tolist and fromlist are larger than the length of the input numnode. The file has 1000 rows, but only the first 500 are populated. Then using e.g. the indices 1937235 and 2589158 must fail.
We cannot guess, what you want to achieve based on the failing code only. So please edit the question and add more details.
  1 comentario
SUNANNA S S
SUNANNA S S el 24 de Mzo. de 2017
Sir, I had tried to get a n by n adjacency matrix in which n denotes the unique number of nodes in the dataset. For eg: A group has six nodes, i.e., a, b, c, d, e, and f .The links of the nodes are ab, ac, ad, ae, ba, bc, bd, bf, be,cd, cf, da, dc, df, ea, ed, ef, and fe. The unique nodes of both followees and followers are a, b, c, d, e, and f . So, I want a 6 by 6 matrix x in which, a is connected to b, c, d, and e; therefore, x12 = x13 = x14 = x15 = 1. By contrast, a is not connected to a and f, therefore x11 = x16 = 0. All the other cells are assigned values using the same method. Thanks

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