I have a phase angle at some amplitude, Please check the image i attached , why is it not getting plotted at particular Angle? I have pasted my code as well,,,anyone help

phase = 26.52867848 amp = 0.463647609 theta_rad = phase ; polar(theta_rad, amp, 'r.');

Output is

: See the red dot,, it should have got plotted at 26 Degree at that particular AMP(Radius)...What is the prob ?

Answer 1

[Star Strider]

It is plotting correctly (the red dot at about 80°) if ‘phase’ is actually in radians. If it’s in degrees and you want to convert it to radians, do the conversion first:

phase = 26.52867848;
amp = 0.463647609;
theta_rad = phase*pi/180;               % Degrees-To-Radians
polar(theta_rad, amp, 'r.')

[L K]

SO after converting to radians, we plot radians and amp value...but why the polar plot is marked with degree values..like 0,90,180... ? why cant't we plot in degrees instead at that particular amplitude?

[Star Strider]

Because that’s the way MathWorks wrote the function!

(I have no better explanation!)

[Image Analyst]

By the way, polar() is deprecated. They recommend you start using polarplot() from now on, if you have R2016a or later.

You might also find deg2rad() or cart2pol() helpful.