How do you create a grouped boxplot with categorical variables on the x-axis.
49 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Jessica Ritz
el 22 de Mzo. de 2017
Comentada: Francisco Javier Perez Sibaja
el 21 de Sept. de 2023
Included is a picture of what I'm trying to do. I downloaded some new functions off of MatLab downloads but they seem to be for numerical variables on both the x and y-axis. I'm looking to group categorical variables on the x-axis of the boxplot. Is there anything I can download or any existing code that does this? Thanks in advance!
0 comentarios
Respuestas (2)
Adam Danz
el 6 de Mzo. de 2020
Editada: Adam Danz
el 6 de Mzo. de 2020
If your boxplot data are matrices with the same number of columns, you can use boxplotGroup() from the file exchange to group the boxplots together with space between the groups.
For example,
data = {rand(100,2), rand(100,2)+.2, rand(100,2)-.2};
boxplotGroup(data, 'PrimaryLabels', {'a' 'b' 'c'}, ...
'SecondaryLabels',{'Group1', 'Group2'}, 'GroupLabelType', 'Vertical')
Example 2
data = {rand(100,2), rand(100,2)+.2, rand(100,2)-.2};
boxplotGroup(data, 'PrimaryLabels', {'a' 'b' 'c'}, ...
'SecondaryLabels',{'Group1', 'Group2'}, 'InterGroupSpace', 2)
4 comentarios
Adam Danz
el 8 de Nov. de 2020
This is from the documentation (current vs.1.2.2).
boxplotGroup(x) receives a 1xm cell array where each element is a matrix with n columns and produced n groups of boxplot boxes with m boxes per group.
So for this input below, there will be 4 groups of 3 boxplots within each group because there are 3 elements of the cell array and each element has 4 columns. That's how you should think about organizing your data.
data = {rand(100,4), rand(20,4)*.8, rand(1000,4)*1.2}
boxplotGroup(data)
It sounds like what you want is,
g{1} = data(1:100, 1:4:end); % or 1:4:9
g{2} = data(1:100, 2:4:end); % or 2:4:10
g{3} = data(1:100, 3:4:end); % etc.....
g{4} = data(1:100, 4:4:end);
mhd z
el 10 de Nov. de 2020
Thank you Adam
I ran the code line by line and figured it out. I was a little comlex :)
its realy a good code. thank you
Iddo Weiner
el 22 de Mzo. de 2017
1 comentario
Francisco Javier Perez Sibaja
el 21 de Sept. de 2023
Thanks for your contribution, it was useful to me!
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!