I am currently doing an exercise in PID control, the first line in the code is
s = tf ('s');
What does it do? according to Mathworks website:
sys = tf(M) creates a static gain M (scalar or matrix)
from what I know that tf is supposed to create a transfer function with a denominator and numerator. what does static gain mean?

 Respuesta aceptada

Star Strider
Star Strider el 1 de Abr. de 2017

2 votos

Using:
s = tf('s');
allows you to enter the transfer function in the next line in symbolic form rather than as numerator and denominator vectors. You can easily recover the numerator and denominator vectors from the system object created:
s = tf('s');
sys = (244.2*s + 244.2) / (0.015*s^4 + 1.525*s^3 + 2.51*s^2 + 245.2*s + 1221);
num = [sys.Numerator{:}]
den = [sys.Denominator{:}]
num =
0 0 0 244.2 244.2
den =
0.015 1.525 2.51 245.2 1221

Más respuestas (2)

Rik
Rik el 1 de Abr. de 2017

0 votos

You could think of this as something similar to uint8(5). It is a way to generate a variable with the correct data-type, so you can more easily manipulate it. Static gain in this case means that you have a transfer function that simply multiplies your input with a number and does nothing else.

1 comentario

Walter Roberson
Walter Roberson el 28 de En. de 2019
not really . the 's' is detected specially. The static gain situation only applies for numeric input.

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Janakiraman S
Janakiraman S el 28 de En. de 2019

0 votos

It creates a continuous time function of variable s (to be given as a text input in quotes) which can be used in defining transfer funtion models
Matlab code and result
s=tf('s')
s =
s
Continuous-time transfer function.

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el 1 de Abr. de 2017

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el 28 de En. de 2019

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