Dont get the required answer..please help

A=[2 5 3 1 1 ; 4 2 5 1 1];
[r,c]=size(A);

B=[1 0 1 1 1; 1 0 1 1 1 ];
[m,n]=size(B);

for row=1:r
    for col=1:c
        for ii=1:m
            for jj=1:n
                if (A(row,col)==5)&&(B(ii,jj)==1)
                    A(row,col)=5+1;

                  end
              end
          end
      end
  end

In the above code, if A has 5 and B has 1 then it should be 6 but if A has 5 but B has 0 then it should be 5. I know its simple. But i am not getting where i am wrong.

[KSSV]

What you are trying to do?

Answer 1

[Guillaume]

Is

A=[2 5 3 1 1 ; 4 2 5 1 1];
B=[1 0 1 1 1; 1 0 1 1 1 ];

A(A == 5 & B) = 6

what you're looking for?

edit, or maybe:

B = logical(B);
A(B) = A(B) + 1

[John D'Errico]

Note that the second solution shown will increment ALL values of A where B == 1. That may or may not be the desired goal. But in that case, it would be as simple to write A=A+B.

[Guillaume]

Indeed! I was too focused on demonstrating logical indexing that I missed the simple addition.

Answer 2

[Rik]

I am going to assume you want the following: A should stay the same, except for some positions. On the positions that A is 5 and B is 1, then A should be 6.

You can solve this without the hassle of 4 nested loops if you use logical indexing.

A(A==5 & B==1)=6;

(Technically, B==1 can be replaced with B, because it already contains only ones and zeros, but this is a more general case)

If this is not what you need, please elaborate on your question. If it is, please mark this answer as accepted answer.