Rehsaping Data Table to new format
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Matt
el 7 de Abr. de 2017
Respondida: Matt
el 10 de Abr. de 2017
Hi, I have a data table that exists like:
[date] [field] [data]
1/1/2017 A 1
1/2/2017 A 2
1/3/2017 A 3
1/1/2017 B 3
1/2/2017 B 2
1/3/2017 B 1
1/1/2017 C 4
1/2/2017 C 5
1/3/2017 C 6
and i want to reshape the data to be like this:
[Date] [A] [B] [C]
1/1/2017 1 3 4
1/2/2017 2 2 5
1/3/2017 3 1 6
so that each unique value in fields becomes a new field name in the new table.
I saw this conversion done in a tutorial the other day, but cant recall how it was done at all, thanks for any input in advance!
Matt
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Respuesta aceptada
Peter Perkins
el 7 de Abr. de 2017
I think you are looking for unstack:
>> t = cell2table( ...
{'1/1/2017', 'A', 1; ...
'1/2/2017', 'A', 2; ...
'1/3/2017', 'A', 3; ...
'1/1/2017', 'B', 3; ...
'1/2/2017', 'B', 2; ...
'1/3/2017', 'B', 1; ...
'1/1/2017', 'C', 4; ...
'1/2/2017', 'C', 5; ...
'1/3/2017', 'C', 6},'VariableNames',{'date' 'field' 'data'});
>> t.date = datetime(t.date,'InputFormat','MM/dd/yyy');
>> t.field = categorical(t.field)
t =
9×3 table
date field data
___________ _____ ____
01-Jan-2017 A 1
02-Jan-2017 A 2
03-Jan-2017 A 3
01-Jan-2017 B 3
02-Jan-2017 B 2
03-Jan-2017 B 1
01-Jan-2017 C 4
02-Jan-2017 C 5
03-Jan-2017 C 6
>> t2 = unstack(t,'data','field')
t2 =
3×4 table
date A B C
___________ _ _ _
01-Jan-2017 1 3 4
02-Jan-2017 2 2 5
03-Jan-2017 3 1 6
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Más respuestas (2)
Steven Lord
el 7 de Abr. de 2017
If your data is stored in a table or timetable, use unstack. The first example on that documentation page is pretty close to the exact scenario you gave, so it should be easy to adapt for your needs.
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