For Loops with Increments Less Than One

3 visualizaciones (últimos 30 días)
cestcandice
cestcandice el 12 de Abr. de 2017
Comentada: cestcandice el 12 de Abr. de 2017
I have to solve this equation with a for loop from 1 to 10 in increments of .01, but what I'm doing isn't working and I don't know why. It works just the way I want to when I take a way the constraint for the increment. Here's what I'm doing:
for t=1:.01:10
x(t)=a*cos((sqrt(g/l))*t)
end

Respuesta aceptada

Matt J
Matt J el 12 de Abr. de 2017
t=1:.01:10;
for i=1:length(t)
x(i)=a*cos((sqrt(g/l))*t(i))
end
  2 comentarios
Matt J
Matt J el 12 de Abr. de 2017
Although, this entire loop could be done in one line,
x=a*cos((sqrt(g/l)) * (1:0.01:10) )
cestcandice
cestcandice el 12 de Abr. de 2017
Oh my gosh! Thank you... I have so much trouble with loops...
Yes, I know it can be done in one line. However, I have to use a for loop.
Thank you!

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Loops and Conditional Statements en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by