error using randi: size inputs must be scalar

I apologize for the incredibly basic question I'm assuming it has something to do with Matlab versions but this old code that is very simple I cannot seem to make it work.

for n = 1:4

a{n} = randint(n,n,[0,9]);

b{n} = randint(n,n,[0,9]);

fprintf(’n = %d:\n’, n), A = a{n}, B = b{n},

end

I changed randint to randi per recommendation of matlab.

EDIT:

I was able to make it work by manipulating the code to this.

for n=1:4

a{n}= randi(9,n)

b{n}= randi(9,n)

fprintf('n = %d:\n', n), A = a{n}, B = b{n},

end

now generates two 4x4 matrices with random numbers between [0,9].

Can somebody explain to me why though? The first formatting looks better than the second one logically.

Answer 1

[Joseph Cheng]

you actually want to do

for n=1:4
    a{n}= randi(10,n)-1;
    b{n}= randi(10,n)-1;
    fprintf('n = %d:\n', n), A = a{n}, B = b{n},
end

as randi(9) is "Generate integer values from the uniform distribution on the set 1:9."

and what you have should be correct and does more than just 2 4x4 matrices. if you scroll up in the command window (as every calculation is displayed because there is no ';' at the end of the lines)

you should see that a and b is a cell array with varying size matrices in each cell

 >> a
 a = 

    [5]    [2x2 double]    [3x3 double]    [4x4 double]

 >> b
 b = 

    [2]    [2x2 double]    [3x3 double]    [4x4 double]

Answer 2

[George Amrhein]

Sorry just trying to understand, your edit makes it so i can get the distribution on the set 0:9 in my matrix correct? instead of 1:9 as it was before

Answer 3

[Walter Roberson]

randi([0 9], n, n)

[George Amrhein]

thanks this makes sense