Comparing matrices of different length
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I have two matrices of different length. For both matrices the first column is x-coordinate, second column is y-coordinate and third column is height. I would like to compare all points for both matrices and for those points where the distance is less than 100 it should calculate the height difference. Is there a smart way of doing this?
3 comentarios
KSSV
el 28 de Abr. de 2017
Question need to be more clear. Let A and B be the set of points; pick one point from A..say A(i,:), you want to pick all the points in B which are less then 100 units of distance from Ai..and like for each and very point for A?
Respuestas (2)
Stephen23
el 28 de Abr. de 2017
Editada: Stephen23
el 28 de Abr. de 2017
If the matrices are not large then you can easily use permute and bsxfun. Here I put the A points down the first dimension, and the B points along the second dimension of the output matrices.
>> A = [0,0,1;10,10,0]; % [X,Y,H]
>> B = [1,1,0;11,11,2;111,111,3]; % [X,Y,H]
>> A3 = permute(A,[1,3,2]);
>> B3 = permute(B,[3,1,2]);
>> H = bsxfun(@minus,A3(:,:,3),B3(:,:,3)); % all height differences
Actually all height differences are in H. If you want to identify the distances between the points, then do this:
>> M = bsxfun(@minus,A3(:,:,1:2),B3(:,:,1:2)); % all X & Y differences
>> D = sqrt(sum(M.^2,3)) % euclidean distance from X & Y differences
D =
1.4142 15.5563 156.9777
12.7279 1.4142 142.8356
>> H(D>=100) = NaN % optional
H =
1 -1 NaN
0 -2 NaN
1 comentario
Stephen23
el 28 de Abr. de 2017
Editada: Stephen23
el 28 de Abr. de 2017
For large matrices you could (possibly) speed up your code by only using one loop, and vectorizing the operations in the inner loop:
A = randi(10000,450000,3);
B = randi(10000,650000,3);
C = {};
for k = 1:size(A,1)
D = sqrt(...
(B(:,1)-A(k,1)).^2 + ...
(B(:,2)-A(k,2)).^2);
idx = D<100;
C{end+1} = B(idx,3)-A(k,3);
end
2 comentarios
Stephen23
el 28 de Abr. de 2017
Editada: Stephen23
el 28 de Abr. de 2017
If memory was not limited, then the fully vectorized approach would be exactly as I showed in my other answer, using bsxfun. The reason to use one loop is simply because (most likely) you are using a PC and have some GB of memory. Using one loop means that the intermediate arrays are of a size that can actually be stored in memory.
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