consecutive rows to define an event
Información
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
Mostrar comentarios más antiguos
Hello everyone, I have a dataset array in which the first column contains the number of each row of the array and the second column is a parameter (0 or 1). I want to find consecutive rows(4 and more) with 1 in the second column and create seperate matrixes with these arrays. I would appreciate any help.
Thanks, Vanessa
Respuestas (1)
Andrei Bobrov
el 15 de Mayo de 2017
Editada: Andrei Bobrov
el 15 de Mayo de 2017
Let A - your dataset with size [N x 2]
Using Image Processing Toolbox
1.
S = regionprops(cumsum(diff([0;A(:,2)]) == 1).*A(:,2) ,'Area','PixelIdxList');
out = cellfun(@(x)A(x,:),{S([S.Area] >= 4).PixelIdxList},'un',0)
2.
i0 = bwareaopen(A(:,2),4);
i1 = bwlabel(i0);
i2 = (1:size(A,1))';
out = accumarray(i1(i0),i2(i0),[],@(x){A(x,:)})
other way without Image Processing Toolbox
1.
ii = cumsum(diff([0;A(:,2)]) == 1).*A(:,2);
t = A(:,2)~=0;
i1 = accumarray(ii(t),1);
i2 = i1>=4;
A1 = A(t,:);
out = mat2cell(A1(ismember(ii(t),find(i2)),:),i1(i2),size(A,2));
2.
ii = cumsum(diff([0;A(:,2)]) == 1).*A(:,2);
C = accumarray(ii+1,(1:size(A,1))',[],@(x){A(x,:)});
C = C(2:end);
out = C(cellfun('size',C,1) >= 4);
1 comentario
Vanessa
el 16 de Mayo de 2017
La pregunta está cerrada.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!