If I start with a matrix of zeros, how can I easily create a triangle of ones in that matrix?
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Daniel Gray
el 19 de Jun. de 2017
Comentada: Image Analyst
el 21 de Jun. de 2017
I want to be able to get a .mat file that will create a filled triangle when I use imagesc. I have been told the easiest way is to start with a matrix full of zeros and then create a triangle of ones inside of that, but I can not figure out how to do that, other than manually which would take a while.
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Respuesta aceptada
KSSV
el 19 de Jun. de 2017
N = 100 ;
T1 = triu(ones(N),1) ;
T2 = fliplr(T1) ;
T = [T2 T1] ;
figure(1)
imagesc(T)
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Más respuestas (3)
Andrei Bobrov
el 19 de Jun. de 2017
N = 1000;
T = tril(ones(N)) ;
a = round(imresize([flip(T,2),T],[round(N/2*tan(pi/3)) N]));
imagesc(a)
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Image Analyst
el 19 de Jun. de 2017
If you have the Image Processing Toolbox, it's a simple one liner:
triangleMatrix = poly2mask(x, y, rows, columns);
where x and y are 3 element arrays of the rows and columns where you want the vertices, and rows and columns are the overall size of your output matrix. Be careful not to mix up x and y with row and column - remember (x,y) = (column,row), not (row, column).
1 comentario
Andrei Bobrov
el 19 de Jun. de 2017
Editada: Andrei Bobrov
el 19 de Jun. de 2017
+1
N = 1000;
k = 1/sqrt(3);
c = round(.5*N*[1-k,4/3;1,1/3;1+k,4/3]);
a = poly2mask(c(:,1),c(:,2),N,N);
imagesc(a)
Adam
el 19 de Jun. de 2017
It depends where you want the triangle. For example
res = tril( ones(100) );
will produce a triangle in the lower left of the matrix.
3 comentarios
Sophia Andaloro
el 21 de Jun. de 2017
I'm wondering the same thing. Let me know if you figure it out.
Image Analyst
el 21 de Jun. de 2017
Like I said, in my answer, poly2mask() will do it, subject to quantization of course.
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