I've been trying to solve this problem, and I understand the programming part of it. However, I don't understand what it means to start from "the unit vector". Could someone please explain what vector the unit vector is referred to?
Generate the Hilbert matrix A of order n=6 and apply 4 iterations of the inverse power method in order to compute an approximation of the eigenvalue \lambda_p that is the closest to p=0.2, starting from the unit vector. Then, use the command eigs to compute the reference ''exact'' value.

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James Tursa
James Tursa el 25 de Jun. de 2017
Editada: James Tursa el 25 de Jun. de 2017

5 votos

A unit vector is any vector v such that norm(v) = 1. For your case of order n=6, you want a 6 element vector v with norm(v) = 1. Some examples of 6-element unit vectors:
v = [1;0;0;0;0;0]
or
v = [1;1;1;1;1;1]; v = v/norm(v);
or
v = rand(6,1); v = v/norm(v);
Any one of these could be used as a suitable starting vector for your problem.

Más respuestas (1)

shahd khalid
shahd khalid el 3 de Abr. de 2020

0 votos

how to find the absolute of value

1 comentario

Erfan Hosseini
Erfan Hosseini el 6 de Oct. de 2021
U can use the below function:
abs(x);
x is the variable u wanna find its absolute value

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