How to create a For loop for a linspace?

I have this code:
for j = 1:20
c(j) = linspace(1,10,length(j));
end
But, the result is a vector "c" with all the values "10":
c= 10 10 10 10 10 10 10....
How can I do to solve the problem? Thnaks

 Respuesta aceptada

Star Strider
Star Strider el 28 de Jun. de 2017
Since in every iteration, ‘j’ is a scalar, the length of ‘j’ will always be 1.
I would just use:
c = linspace(1, 10, 20);
or if you actually want varying-length vectors, save ‘c’ as a cell array:
for j = 1:20
c{j} = linspace(1,10,j);
end

5 comentarios

The problem is that I have to use the linespace in a "scatter" function:
for i = 1:length(temp_discesa_i)
pause(0.1)
c = linspace(1, 10, length(temp_discesa_i));
scatter(temp_discesa_i(i), spazio_discesa_i(i),30,c,'filled')
pause(0.01);
end
and Matlab give me an error: "Error using scatter (line 93) CData must be an RGB triplet, an M-by-1 vector of the same length as X, or an M-by-3 matrix."
Steven Lord
Steven Lord el 28 de Jun. de 2017
The loop variable i is a scalar. So you're creating a scatter plot of one point with x=temp_discesa_i(i) and y=spazio_discesa_i(i) each time. In that case, the color input must be an RGB triplet or a scalar that is mapped into the colormap. In order to achieve what I think you want to do with this code, create the linspace vector prior to the for loop and index into c the same way you index into temp_discesa_i and spazio_discesa_i.
But creating a scatter plot for one point at a time seems like a bit of overkill. Are you sure you don't want to simply create a line once and update its XData, YData, MarkerFaceColor, and MarkerEdgeColor properties in the loop? Or would scatter plotting all the data at once be acceptable?
@Steven — Thank you.
I am not certain what the objective is. My suggestion is to define the colormap before the loop, as:
c = colormap(jet(length(temp_discesa_i)));
then do the plotting as:
scatter(temp_discesa_i(i), spazio_discesa_i(i),30,c(i,:),'filled')
awaiting further details.
Michela Longhi
Michela Longhi el 28 de Jun. de 2017
Yes!!!! It's now working. Thank you to all.
Star Strider
Star Strider el 28 de Jun. de 2017
Our pleasure!

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