How to solve differential equation with variable input parameters

How to solve differential equation: zdot = (w*v*z)+1. where w=constant, v= velocity array of size 10, z is the initial condition=0. The solution for the first step is the z value for the next step.

Answer 1

[Torsten]

z0=0
z1=z0+dt*(w*v1*z1+1) -> z1=(z0+dt)/(1-dt*w*v1)
z2=z1+dt*(w*v2*z2+1) -> z2=(z1+dt)/(1-dt*w*v2)
...

In general:

Use the recursion

z(i+1)=(z(i)+dt)/(1-dt*w*v(i+1)) (i=1,...,9)

with

z(1)=0

Best wishes

Torsten.

[Swagato Das]

Thank you. The solution provided is working fine.But I was looking for a solution using functions, such as 'ode'. This is only a small part of the equation to be solved.

[Torsten]

Then, with your time-dependent vector v, you can adapt the example "ODE with Time-Dependent Terms" provided under

https://de.mathworks.com/help/matlab/ref/ode45.html

Best wishes

Torsten.

[Swagato Das]

Thank you sir..