Find the precision of a value

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Konstantinos Tsitsilonis
Konstantinos Tsitsilonis el 4 de Jul. de 2017
Editada: Stephen23 el 26 de Sept. de 2017
Hello,
Is there a function in matlab that returns the precision of a number? for example, if I have a number 5.34 i want it to return 0.01, if I have a number 4 I want it to return 1 etc..
Thanks in advance for your answers,
  2 comentarios
Adam
Adam el 4 de Jul. de 2017
Given that many double-precision numbers cannot be represented to an exact level of accuracy this would be problematic. e.g.
>> a = 5.34
a =
5.34
>> sprintf( '%0.20f', a )
ans =
'5.33999999999999990000'
You would want this to return 0.01 which may be reasonable, but actually the precision (to use your term) of the number is way smaller.
José-Luis
José-Luis el 4 de Jul. de 2017
Your question might make sense if your number is stored as a string, which your using the fprintf tag suggests.

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Respuesta aceptada

Stephen23
Stephen23 el 4 de Jul. de 2017
Editada: Stephen23 el 4 de Jul. de 2017
No doubt there will be disagreements over what it means for floating point numbers, but here is one solution which provides the least unexpected output by converting to string, converting the last non-zero digit to 1 and the rest to 0. I do not claim that it is fast, but it does seem to be reasonably robust.
function p = getprecision(x)
f = 14-9*isa(x,'single'); % double/single = 14/5 decimal places.
s = sprintf('%.*e',f,x);
v = [f+2:-1:3,1];
s(v) = '0'+diff([0,cumsum(s(v)~='0')>0]);
p = str2double(s);
end
and tested:
>> getprecision(5.34)
ans = 0.010000
>> getprecision(5)
ans = 1
>> getprecision(53400)
ans = 100
Notes:
  1. keep in mind that 5.34 and 0.01 do not really exist in binary floating point numbers. See Adam's comment.
  2. '%g' is an obvious choice, but is actually more complicated because it can return fixed point values with trailing zeros.
  1 comentario
Jan
Jan el 4 de Jul. de 2017
+1: "the least unexpected output" is a nice definition of a "best solution".

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Más respuestas (2)

José-Luis
José-Luis el 4 de Jul. de 2017
Just in case your number is stored as a string:
bla = '5.14';
result = strsplit(bla,'.');
result = numel(result{2})
There are better (faster) ways to do this, but coffee calls.
  2 comentarios
Stephen23
Stephen23 el 4 de Jul. de 2017
Editada: Stephen23 el 4 de Jul. de 2017
What about:
bla = '534000';
bla = '0.000045';
bla = '2463.00000';
José-Luis
José-Luis el 4 de Jul. de 2017
Then a regex() could work.

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James Tursa
James Tursa el 5 de Jul. de 2017
Editada: Stephen23 el 26 de Sept. de 2017

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