Solve is not returnig solution - matlab

Hi,
I'm trying to find the vector x=[x1 ; x2 ; x3 ; x4 ; x5] by solving:
Valorantigo(1,1)=3441/(1-0.00302+x1) + 3441/(1-0.00261+x1)^2 + 301720.5/(1-0.00208+x1)^3
Valorantigo(2,1)=68750/(1-0.00302+x2) + 1068750/(1-0.00261+x2)^2 + 0/(1-0.00208+x2)^3
Valorantigo(3,1)=170040/(1-0.00302+x3) + 13085020/(1-0.00261+x3)^2 + 0/(1-0.00208+x3)^3
Valorantigo(4,1)=229350/(1-0.00302+x4) + 229350/(1-0.00261+x4)^2 + 5729350/(1-0.00208+x4)^3
Valorantigo(5,1)=34194000/(1-0.00302+x5) + 0/(1-0.00261+x5)^2 + 0/(1-0.00208+x5)^3
My code is:
A=[99.23;100.05;91;107.71;104.1];
B=[3441 3441 301720.5;68750 1068750 0;170040 13085020 0;229350 229350 5729350;34194000 0 0];
N=[300000;1000000;13000000;5500000;32800000];
E=[-0.00302;-0.00261;-0.00208];
[c3,r3]=size(A);
[c4,r4]=size(B);
Valorantigo(1:c3,1)=A(1:c3,1).* N(1:c3,1) ./100;
x=sym ('x',[1 c3]);
x=transpose(x);
for i=1:c3
Valor(i,1)=symfun(0,x);
for j=1:r4
Valor(i,1)=symfun((Valor(i,1)/(1+E(j,1)+x(i,1))^j)+((B(i,j)/((1+E(j,1)+x(i,1))^j))),x);
end
end
eqn=Valor(1:c3,1)==Valorantigo(1:c3,1);
[x1,x2,x3,x4, x5, param, cond] = solve(eqn, x, 'ReturnConditions', true);
But the solve don't return any value, can you understand why?

1 comentario

Jan
Jan el 19 de Jul. de 2017
The more threads you open for a specific question, the higher is the level of confusion for the ones, who want to assist you.

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Respuestas (1)

Torsten
Torsten el 17 de Jul. de 2017
function main
x0=ones(5,1);
sol=fsolve(@myfun,x0)
function F=myfun(x)
A=[99.23;100.05;91;107.71;104.1];
B=[3441 3441 301720.5;68750 1068750 0;170040 13085020 0;229350 229350 5729350;34194000 0 0];
N=[300000;1000000;13000000;5500000;32800000];
E=[-0.00302;-0.00261;-0.00208];
[c3,r3]=size(A);
[c4,r4]=size(B);
Valorantigo(1:c3)=A(1:c3).*N(1:c3)./100;
for i=1:c3
Valor(i)=0.0;
for j=1:r4
Valor(i)=Valor(i)+B(i,j)/(1+E(j)+x(i)^j);
end
F(i)=Valor(i)-Valorantigo(i);
end
Note that your 5th equation does not have a zero - so you will have to exclude it from the above calculation.
Best wishes
Torsten.

6 comentarios

Mariana Ferreira
Mariana Ferreira el 17 de Jul. de 2017
Thanks. Could u explain better that about the 5th equation? I'm not understanding.
John D'Errico
John D'Errico el 17 de Jul. de 2017
Editada: John D'Errico el 17 de Jul. de 2017
Valorantigo(5,1)=34194000/(1-0.00302+x5) + 0/(1-0.00261+x5)^2 + 0/(1-0.00208+x5)^3
But see that TWO of the terms are zero ALWAYS. They are 0/stuff. So the 5th equation reduces to trying to solve for x5, such that
34194000/(1-0.00302+x5) == 0
Under what circumstances with that EVER be zero? NONE. There is no real or complex value for x5 that makes the left hand side zero.
But
Valorantigo(5,1)==34144800
so it will be
34194000/(1-0.00302+x5) == 34144800
Torsten
Torsten el 18 de Jul. de 2017
You are right.
Best wishes
Torsten.
Mariana Ferreira
Mariana Ferreira el 18 de Jul. de 2017
Now that I checked the solution obtained is not right, for the first should be 1,4299, for the second 7,1098 and so on. I tried to include optimset but didnt work.
Torsten
Torsten el 19 de Jul. de 2017
Editada: Torsten el 19 de Jul. de 2017
If you insert the above values in the first and second equation, you will see that they don't solve them.
But - as Jan pointed out - there is an error in the code: a parenthesis is set incorrectly.
Use
Valor(i)=Valor(i)+B(i,j)/(1+E(j)+x(i))^j;
instead of
Valor(i)=Valor(i)+B(i,j)/(1+E(j)+x(i)^j);
Best wishes
Torsten.

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el 17 de Jul. de 2017

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Jan
el 19 de Jul. de 2017

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