Create a 4D matrix with specific range values
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Bruno Silva
el 29 de Ag. de 2017
Respondida: Image Analyst
el 29 de Ag. de 2017
I would like to create a 4D matrix with specific range values:
For the first dimension, values from [5 10 15 ... 200] so basically 5*[1:40]
For the second dimension, values from the list [8 10 20 25 40 50 100 200]
For the third dimension, values from [1 2 3 ... 10] so [1:10]
For the fourth dimension, values from [1 2 ... 50] that is [1:50]
When accessing a specific "value" of that matrix, I would like to be able to view these rages that I've set up for each dimension. For example: A(2,1,2,3) = [10 8 2 3] (in this case)
How can I do that?
Thank you.
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Image Analyst
el 29 de Ag. de 2017
Editada: Image Analyst
el 29 de Ag. de 2017
No. You can't have a vector of 4 numbers at a particular location. You can just have a single number as James said. And you didn't even explain it - you just repeated what you said first. Let's say the "A" is a video, so we have row and column as the first two indexes, The red green or blue value as the third index, and frame number as the 4th index. So A(2,1,2,3) would be row 2, column1 of color channel #2 (blue) and you're looking at frame #3 (because the 4th index is 3). Now the blue value is one value -- it can't be a vector of 4 blue values. Please supply context as to what this 4-D array represents. When you send in indexes to A, what do those indexes represent?
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Image Analyst
el 29 de Ag. de 2017
You can store the error
In quadruple loop over all 4 parameters...
theActualValue = whatever(..........
thisError = SomeFunctionToComputeError(theActualValue, theExpectedTrueValue);
% Save error for this combination of parameters.
A(samplingRate, windowSize, numLayers, numNeurons) = thisError;
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James Tursa
el 29 de Ag. de 2017
Editada: James Tursa
el 29 de Ag. de 2017
Here is one way to do what you have asked, although I don't really know if this is the best way to go about coding the real problem you are trying to solve:
D1 = 5:5:200;
D2 = [8 10 20 25 40 50 100 200];
D3 = 1:10;
D4 = 1:50;
A = @(a,b,c,d) [D1(a) D2(b) D3(c) D4(d)]
Then, e.g.
>> A(2,1,2,3)
ans =
10 8 2 3
In this case, A is actually a function handle and not a 4D matrix. But it will yield the vector result you want when passed four inputs that are used to index into your "dimension" vectors.
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