what is wrong with my code ?
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ajeet verma
el 31 de Ag. de 2017
Editada: ajeet verma
el 31 de Ag. de 2017
i generate a code to get the desired result as given in attached file but there is some problems in step-3, and i am unable to find desired result from step-3 so please help me where am i wrong, my code is here:
%
% STEP FIRST
clc;
clear all;
Imax=0.8;
Imin=0.2;
Im=Imax-Imin;
T = 20;
s1= @(x) ((2*Im*x/T)+Imin+Im/2).*(0<=x & x<=T/4) +((-2*Im*x/T)+Imin+3*Im/2).*(T/4<=x & x<=3*T/4)+((2*Im*x/T)+Imin-3*Im/2).*(3*T/4<=x & x<=T);
s2= @(x) ((-2*Im*x/T)+Imin+Im/2).*(0<=x & x<=T/4) + ((2*Im*x/T)+Imin-Im/2).*(T/4<=x & x<=3*T/4)+((-2*Im*x/T)+Imin+5*Im/2).*(3*T/4<=x & x<=T);
x = linspace(0, 20);
X = repmat(x, 1000, 10);
I1 = s1(x);
I2 = s2(x);
figure(1),plot(x,I1)
figure(2),plot(x,I2)
%%STEP-2 (wrapped map)
r0=abs(I1-I2)/Im;
figure(3),plot(x,r0)
%%STEP-3 (intensity ratio)
R=2;
r=2*round((R-1)/2)+((-1)^R+1)*r0;
figure(4),plot(x,r)
please find attachments
2 comentarios
Respuesta aceptada
John D'Errico
el 31 de Ag. de 2017
Editada: John D'Errico
el 31 de Ag. de 2017
Just explaining what KSSV said:
r=2*round((R-1)/2)+((-1)^R+1)*r;
See that r lies on BOTH sides of the equality here. But since it has never been used before, what is r? Should MATLAB somehow be smart enough that it can solve for r here? Or is that a typo? Never ask a computer to magically determine what you really intended to do, even if what you intended is not what you wrote. (The mind reading toolbox is not yet out of beta test stage.)
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