How to troubleshoot solver when wrong variable is showing up?

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Suzie Oman
Suzie Oman el 11 de Sept. de 2017
Comentada: Rik el 12 de Sept. de 2017
When using solver, I am getting a variable that is not in my equation in the solution. What should I troubleshoot?
I am solving an 5 degree polynomial with t as the only variable, and instead of one answer (there should only be one), there are five answers that include a 'z' (yes,'z', that's not a typo).
  3 comentarios
Suzie Oman
Suzie Oman el 11 de Sept. de 2017
I am using the solve command. Below are the equations where x,y and Q are functions of t.
Q = (1543*t)/100 - 3993/1000; x = (27*t)/8 - 4503607640442835/5070602400912917605986812821504; y = (3641*t)/250 - 42321/1000;
rhs = p00 + p10*x + p01*y + p20*x.^2 + p11*x.*y + p02*y.^2 + p30*x.^3 + p21*(x.^2).*y + p12*x.*y.^2 + p03*y.^3 + p40*x.^4 + p31*(x.^3).*y + p22*(x.^2).*y.^2 + p13*x.*y.^3 + p04*y.^4 + p50*x.^5 + p41*(x.^4).*y + p32*(x.^3).*y.^2 + p23*(x.^2).*y.^3 + p14*x.*y.^4 + p05*y.^5;
tsoln = solve(lhs == rhs,t)
Rik
Rik el 12 de Sept. de 2017
Are all those p values supposed to be syms as well? What code are you using to define your variables? A good strategy is to try to condens your problem to the smallest piece of code that reproduces the problem: a MWE (or MFE, minimal failing example). Then we can run your code and try to fix it that way (and see if we can reproduce it on our OS release combination).
(note that Q is unused and you haven't defined lhs in your comment above)

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