cell array into 3d matrix
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i have a cell array of size 104x104 with each cell having a matrix of size 1x1000. How can i convert this cell into a 3d matrix of size 104x104x1000 ??
1 comentario
Sean de Wolski
el 17 de Abr. de 2012
+1, good clear question with room for many good approaches
Respuestas (4)
Hanan Shteingart
el 17 de Nov. de 2013
6 votos
You can concatenate cell array content using the "cat" function with this syntax: cat(dim, A{:}) where A is your cell array
the cyclist
el 17 de Abr. de 2012
Both of these should do the same thing (and I think it is the thing you want). The second is a little bit more transparent, but slower.
B1 = cell2mat(arrayfun(@(x)permute(x{:},[3 1 2]),A,'UniformOutput',false));
B2 = zeros(104,104,1000);
for i = 1:104,
for j = 1:104,
B2(i,j,1:1000) = permute(A{i,j},[1 3 2]);
end
end
1 comentario
Sean de Wolski
el 17 de Abr. de 2012
Reshape() instead of permute() for speed.
Sean de Wolski
el 17 de Abr. de 2012
Or the pure matrix manipulation approach:
%Sample Data:
X = reshape(magic(50),1,[]);
C = cell(100,100);
C(:) = {X}; %100 x 100 cell array of xs
%Engine:
D = reshape(reshape(cell2mat(C)',numel(X),numel(C))',size(C,1),size(C,2),numel(X)); %some reshapin'
%Check
all(all(all(bsxfun(@eq,D(1,1,:),D)))) %Is it right?
yay!
Andrei Bobrov
el 17 de Abr. de 2012
Editada: Andrei Bobrov
el 17 de Nov. de 2013
permute(reshape(cell2mat(C).',numel(C{1}),size(C,2),[]),[3 2 1])
or
reshape(cat(1,A{:}),[size(C), numel(C{1})])
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