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How can I fix the "Subscript indices must either be real positive integers or logicals." I am getting the errors my j(k) and l(k). my program works when I change the range but i only get ending term, any point in the right direction would be helpfu

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z(1) = 1.5;
for k = 1:6
fprintf('%d %5.8f %5.8f %5.8f\n',n , z(k), e(k), p(k));
z(k+1) = (.5)*z(k) + sqrt(2)/2*z(k);
x(k) = z(k+1);
e(k) = z(k+1) - sqrt(2);
j(k)= log((e(k))/log(e(k-1)));
l(k)= log(e(k-1))/log(e(k-2));
p(k) = j(k)/l(k);
end

Respuesta aceptada

Robert U
Robert U el 27 de Sept. de 2017
Editada: Robert U el 27 de Sept. de 2017
Hi Janvier Solaris,
the main problem despite of posting non-executable code is the reference to e(k-2) for l(k) calculation. Since indices have to a positive integers or logicals it will not work for k <= 2. That code snippet does:
z(1) = 1.5;
for k = 1:6
z(k+1) = (.5)*z(k) + sqrt(2)/2*z(k);
x(k) = z(k+1);
e(k) = z(k+1) - sqrt(2);
if k > 2
j(k)= log((e(k))/log(e(k-1)));
l(k)= log(e(k-1))/log(e(k-2));
p(k) = j(k)/l(k);
fprintf('%d %5.8f %5.8f %5.8f\n',k , z(k), e(k), p(k));
end
end
Kind regards,
Robert
  1 comentario
Janvier Solaris
Janvier Solaris el 27 de Sept. de 2017
Thank You @Robert, I was afraid that was my issue but instead of using an if statement I was starting at k = 3 to try and fix it but it was not working. Your fix cleared it. I am fairly new to Matlab and your help is much appreciated

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