Solving coupled Differential equations

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JaeSung Choi
JaeSung Choi el 11 de Oct. de 2017
Comentada: JaeSung Choi el 15 de Oct. de 2017
I tried to solve following diff. eq. using 'dsolve' but (maybe) it's impossible.
So please help me how to solve following eq.s using matlab!!!!!
syms s1 s2 s3 g1 g2 g3 p1 p2 p3 t
h = 1; b = 2; e = exp(1); v = 1;
diffqp1 = 'Dp1 = h*b*s1*(g1-p3)-(e/v)*p1'
diffqp2 = 'Dp2 = h*b*s1*(g1-p3)-(e/v)*p2'
diffqp3 = 'Dp3 = h*b*s1*(g1-p3)-(e/v)*p3'
diffqs1 = 'Ds1 = -h*b*s1*(g1-p3)-(e/v)*s1'
diffqs2 = 'Ds2 = -h*b*s1*(g1-p3)-(e/v)*s2'
diffqs3 = 'Ds3 = -h*b*s1*(g1-p3)-(e/v)*s3'
  3 comentarios
Walter Roberson
Walter Roberson el 11 de Oct. de 2017
  • Are your g1 g2 g3 functions or constants?
  • What boundary conditions are there?
  • you never use g2 or g3 but use g1 repeatedly
Presuming that g1 is a constant and not a function, then current syntax would look like
syms s1(t) s2(t) s3(t) g1 g2 g3 p1(t) p2(t) p3(t)
h = 1; b = 2; e = exp(1); v = 1;
Dp1 = diff(p1); Dp2 = diff(p2); Dp3 = diff(p3);
Ds1 = diff(s1); Ds2 = diff(s2); Ds3 = diff(s3);
diffqp1 = Dp1 == h*b*s1*(g1-p3)-(e/v)*p1;
diffqp2 = Dp2 == h*b*s1*(g1-p3)-(e/v)*p2;
diffqp3 = Dp3 == h*b*s1*(g1-p3)-(e/v)*p3;
diffqs1 = Ds1 == -h*b*s1*(g1-p3)-(e/v)*s1;
diffqs2 = Ds2 == -h*b*s1*(g1-p3)-(e/v)*s2;
diffqs3 = Ds3 == -h*b*s1*(g1-p3)-(e/v)*s3;
eqns = [diffqp1, diffqp2, diffqp3, diffqs1, diffqs2, diffqs3];
sol = dsolve(eqns);
JaeSung Choi
JaeSung Choi el 15 de Oct. de 2017
Really thanks for your comment. I'm sorry for that I forgot some constants.

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