How to read a sequence of files with same extension and store it

Hello Everyone, I have N number of text cards, lets say 200 cards with similar extension, the extension is (07), I wrote a code to open each card individually and store it in vectors with fixed width columns. Now to import or export multiple files, how can I create a control loop to process one file at a time Automatically? knowing that each card has the same number of columns but different rows, Example one has 2500 rows and other has 1700 . %to read each card I wrote:

fileID = fopen('C77901XX.07','r');
formatSpec = '%s';
A_cell = textscan(fileID,formatSpec);
for i=1:size(A_cell{1},1)
    A(i,:)=char(A_cell{1,1}{i});
end 
and the code to separate columns is :

y=A;
[rows,columns]=size(A);
% % This for loop is to read the data row by row and store in different
% % matrices
for i=1:rows
    Record_Type(i,:)=y(i,1:1);
    FIPS_State_Code(i,:)=y(i,2:3);
    Station_ID(i,:)=y(i,4:9);
    Direction_of_Travel_Code(i,:)=y(i,10:10);
    Lane_of_Travel(i,:)=y(i,11:11);
    Year_of_Data(i,:)=y(i,12:13);
    Month_of_Data(i,:)=y(i,14:15);
    Day_of_Data(i,:)=y(i,16:17);
    Hour_of_Data(i,:)=y(i,18:19);
    Total_Volume(i,:)=y(i,20:24);
    Class_1_Count (i,:)=y(i,25:29);
    Class_2_Count (i,:)=y(i,30:34);
    Class_3_Count (i,:)=y(i,35:39);
    Class_4_Count (i,:)=y(i,40:44);
    Class_5_Count (i,:)=y(i,45:49);
    Class_6_Count (i,:)=y(i,50:54);
    Class_7_Count (i,:)=y(i,55:59);
    Class_8_Count (i,:)=y(i,60:64);
    Class_9_Count (i,:)=y(i,65:69);
    Class_10_Count (i,:)=y(i,70:74);
    Class_11_Count (i,:)=y(i,75:79);
    Class_12_Count (i,:)=y(i,80:84);
    Class_13_Count (i,:)=y(i,85:89);
    Class_14_Count (i,:)=y(i,90:94);
    Class_15_Count (i,:)=y(i,95:99);
end

how can I please do this to the whole cards by one click? and by the way I wrote this to find the cards with the same extension in the folder:

path =pwd; 
extension = '.07' 
rtnFiles=dir(fullfile(path,['*' extension]))

Thank you guys

Answer 1

[KSSV]

To read all the .07 files:

myfiles = dir('*.07') ;
N = length(myfiles) ;    % total number of files 
data = cell(N,1) ;       % to store the data of each file into cell
% loop for each file 
for i = 1:N
    thisfile = files(i).name ;
    % read the file/ do waht you want / you may run your code here 
    % data{i} = file data ;  % store file data like this into cell
end

[MAHMOUD ALZIOUD]

Thank you for your help, I just tried it and it still gives: Undefined variable "files" or class "files". what does this mean?

[KSSV]

Copy your code here.....files should be a structure of all files with extension.07 present in the folder.

[MAHMOUD ALZIOUD]

Ok this is my code:

fileID = fopen('C77901XX.07','r');
formatSpec = '%s';
A_cell = textscan(fileID,formatSpec);
for i=1:size(A_cell{1},1)
    A(i,:)=char(A_cell{1,1}{i});
end 
and the code to separate columns is :
y=A;
[rows,columns]=size(A);
% % This for loop is to read the data row by row and store in different
% % matrices
for i=1:rows
    Record_Type(i,:)=y(i,1:1);
    FIPS_State_Code(i,:)=y(i,2:3);
    Station_ID(i,:)=y(i,4:9);
    Direction_of_Travel_Code(i,:)=y(i,10:10);
    Lane_of_Travel(i,:)=y(i,11:11);
    Year_of_Data(i,:)=y(i,12:13);
    Month_of_Data(i,:)=y(i,14:15);
    Day_of_Data(i,:)=y(i,16:17);
    Hour_of_Data(i,:)=y(i,18:19);
    Total_Volume(i,:)=y(i,20:24);
    Class_1_Count (i,:)=y(i,25:29);
    Class_2_Count (i,:)=y(i,30:34);
    Class_3_Count (i,:)=y(i,35:39);
    Class_4_Count (i,:)=y(i,40:44);
    Class_5_Count (i,:)=y(i,45:49);
    Class_6_Count (i,:)=y(i,50:54);
    Class_7_Count (i,:)=y(i,55:59);
    Class_8_Count (i,:)=y(i,60:64);
    Class_9_Count (i,:)=y(i,65:69);
    Class_10_Count (i,:)=y(i,70:74);
    Class_11_Count (i,:)=y(i,75:79);
    Class_12_Count (i,:)=y(i,80:84);
    Class_13_Count (i,:)=y(i,85:89);
    Class_14_Count (i,:)=y(i,90:94);
    Class_15_Count (i,:)=y(i,95:99);
end

Note in the code I wrote C77901XX which is the file ID, I need this code to write all the files that have the extension of 07 and store each file outputs in a separate file please