Debug of a very simple recursion problem
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The idea of the problem is to reverse a character array using recursion.
1. Write a function called charReversal with the following function signature:
1 f u n c ti o n a r r a y 2 = c h a r R e v e r s al ( a r r a y 1 )
where array1 is the input character array, and array2 is the reversal of array1. For example, charReversal(’abcde’) should return ’edcba’.
My answer:
function array2 = charReversal(array1)
%arrary1 is the input character array
%arrary2 is the reversal of array1
if numel(array1)<2
array2 = array1;
else
array2 = reverse(array1);
end
Question: I don't know where to to put the base case, what the base case should be.
Thank you very much.
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Respuestas (1)
Walter Roberson
el 21 de Oct. de 2017
if numel(array1)<2
array2 = array1;
is already handling the base case. But the rest of your code needs to be developed to use recursion.
2 comentarios
Walter Roberson
el 21 de Oct. de 2017
The function does not call itself, and does not call any function that calls the function, so No, it is not already recursive.
Hint:
What happens if you remove one character and reverse the rest, and then somehow combine the one removed character with what was returned from reversing the rest?
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