Hi,
I have a 3x1 array, a = [1 2 3]', and B, a 3x2 matrix.
How can I create C, a 6x2 matrix, whose first row is the same as B and repeated once [a(1)], the second row is the second row of B repeated twice [a(2)], and the third row is the third row of B repeated three times [(a(3)]? I'm trying to use the repelem function but am a bit stuck...Do I have to loop to do this, or is there another way?
Any help would be appreciated. Thx in advance,
DB

 Respuesta aceptada

Cedric
Cedric el 22 de Oct. de 2017

0 votos

Here is one way to achieve it. If
>> a = [1;2;3] ;
>> B = randi( 10, 3, 2 )
B =
3 10
6 2
10 10
Then
>> C = arrayfun( @(k)repelem(B(k,:),a(k),1), 1:numel(a), 'UniformOutput', false ) ;
>> C = vertcat( C{:} )
C =
3 10
6 2
6 2
10 10
10 10
10 10

2 comentarios

dan berkowitz
dan berkowitz el 23 de Oct. de 2017
thank you!
Cedric
Cedric el 23 de Oct. de 2017
My pleasure!

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Etiquetas

Preguntada:

el 22 de Oct. de 2017

Comentada:

el 23 de Oct. de 2017

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by