Summation of Infinity Terms

I have this question to solve :
Then I have written the code below but it does not work. The main problem is three on index numbers. How to use in MATLAB ? Also I would like to calculate the value of it, not symbolic.

2 comentarios

David Goodmanson
David Goodmanson el 25 de Oct. de 2017
Hi Berkcan,
since sin(m*pi) = 0 for all integer m, every term in this series is zero. Something has to be wrong here.
Roger Stafford
Roger Stafford el 25 de Oct. de 2017
Editada: Roger Stafford el 25 de Oct. de 2017
@David. I agree. I didn't notice that.

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Respuestas (1)

Roger Stafford
Roger Stafford el 25 de Oct. de 2017
Editada: Roger Stafford el 25 de Oct. de 2017

0 votos

In the summation symbol ‘m’ is supposed to range over only the odd positive integers. You have it ranging over all positive integers. Try this:
D = 400/pi*symsum(1/(2*p-1)*sinh((2*p-1)*pi/4)/sinh((2*p-1)*pi)*sin((2*p-1)*pi),p,1,inf);

5 comentarios

David Goodmanson
David Goodmanson el 25 de Oct. de 2017
Hi Roger, see comment above.
Berkcan Oz
Berkcan Oz el 26 de Oct. de 2017
Thanks for the code, but I did not understand what you did there. How can I calculate the value of whole sum ?
Roger Stafford
Roger Stafford el 26 de Oct. de 2017
@Berkcan: What I did was to replace each p in your expression by 2*p-1. That way as p advances through all possible positive integers, 1, 2, 3, ..., then 2*p-1 will advance through the odd-valued positive integers, 1,, 3, 5, ...
However, you will first have to address the problem pointed out by David, namely that sin(p*pi) is identically zero for all integer-valued p. As it stands, the value of V would be zero.
Berkcan Oz
Berkcan Oz el 26 de Oct. de 2017
Yeah, I understood right now, so, appreciate to you. How can I fix that problem ? If you tell me a solution, I'll try to write a code then share here.
Roger Stafford
Roger Stafford el 26 de Oct. de 2017
You can only fix the problem pointed out by David by correcting the function you wrote originally. Make sure you have it right.

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