Im trying to model a two coil (AC) wireless power transfer. Could anyone help me with my code? (Solving differential equations).
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Jack Levy
el 31 de Oct. de 2017
Respondida: Matheus Marchiori
el 9 de Abr. de 2019
Im trying to solve a two coil power transfer circuit on Matlab using AC supply. Can anyone help me? This is what i have done so far:
Im getting an error in line 17.
syms I_1(t) I_2(t)
syms t
w=4;
t=0:pi/100:2*pi; %this creates a vector of values for t, from 0 to 2*pi in pi/100 increments.
y=sin(w*t); %takes sin of w * all the values in the t vector plot(t,y)
V_0 = y; %maximum voltage
R_1 = 10; %resistor 1
R_2 = 20; %resistor 2
L_1 = 0.055; %inductor 2
L_2 = 0.075; %inductor 2
k = 0.75; %coupling coefficient
M_12 = k*sqrt(L_1*L_2); %caculating mutual inductance
ode1 = diff(I_1) == (V_0- (R_1*I_1)+(M_12*I_2))/L_1;
ode2 = diff(I_2) == ((R_2*-I_2)-(M_12*I_1))/L_2;
odes = [ode1; ode2];
S = dsolve(odes);
I_1Sol(t) = S.I_1;
I_2Sol(t) = S.I_2;
[I_1Sol(t), I_2Sol(t)] = dsolve(odes);
cond1 = I_1(0) == 0;
cond2 = I_2(0) == 1;
conds = [cond1; cond2];
[I_1Sol(t), I_2Sol(t)] = dsolve(odes,conds);
fplot(I_1Sol)
hold on
fplot(I_2Sol)
grid on
legend('I_1Sol','I_2Sol','Location','best')
1 comentario
M
el 31 de Oct. de 2017
This will not answer your question, but why are you defining syms t and then redefining t = 0:pi/100:2*pi ?
Respuesta aceptada
Birdman
el 31 de Oct. de 2017
Your mistake is to define t vector numerically before solving differential equations. If you do so, the solver tries to differentiate the function with repsect to 0 and as a result, gives an error. To get rid of this situation, you need to define t vector after the line
[I_1Sol(t), I_2Sol(t)] = dsolve(odes,conds);
Since t is a symbolic variable, it will be better if you insert numerical values as:
t=subs(t,0:pi/100:2*pi)
2 comentarios
Birdman
el 31 de Oct. de 2017
Editada: Birdman
el 31 de Oct. de 2017
When I substitute t with your vector, elements of I_1 and I_2 becomes NaN. Maybe you should change your initial conditions or check your ode equations.
By the way, if the answer helped you, you can accept the answer so that other people having the same problem will know there is a working solution.
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Matheus Marchiori
el 9 de Abr. de 2019
Hi Jack. Can you send the full script after this changes? Thank you!
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