Convertion from grayscale value to RGB vector
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Hello, I am trying to figure out how I have to convert a grayscale value which has been exracted from a grayscale frame of an avi video to the right RGB value (vector). I am using the code below:
if true
% Extract frames from video and save it on an Array
folder = fileparts(which('diffusion_process.avi'));
movieFullFileName= fullfile(folder,'diffusion_process.avi');
videoObject = VideoReader(movieFullFileName);
numberOfFrames = videoObject.NumberOfFrames;
for frame = 1:numberOfFrames
thisFrame = read(videoObject,frame);
if frame == 1
h = size(thisFrame,1);
w = size(thisFrame,2);
processo = zeros(h, w, 3, numberOfFrames);
end
processo(:, :, :, frame) = thisFrame;
end
i = 1;
Color=[processo(X,Y,1,i),processo(X,Y,1,i),processo(X,Y,1,i)];
end
The vector called Color always returns white. I am not sure if I have set the RGB vector in the correct way. Any suggestions? Many thanks Davide
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Respuestas (1)
Jan
el 13 de Nov. de 2017
Editada: Jan
el 13 de Nov. de 2017
Your processo array is a double array with the range [0, 1], but the frames obtained from the movie might have the type INT8 with a range of 0:255. Then all but a 0 value produces a white color in the double array. Convert the types:
processo(:, :, :, frame) = im2double(thisFrame);
or:
processo(:, :, :, frame) = double(thisFrame) / 255;
2 comentarios
Guillaume
el 13 de Nov. de 2017
Editada: Guillaume
el 13 de Nov. de 2017
Alternatively, create processo so that it is the same class as the frame:
%in the if block
processo = zeros(h, w, 3, numberOfFrames, 'like', thisFrame);
This will use less memory than converting the whole lot to double (8 times the memory of an uint8 array)
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