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How to construct a Sliced Reduction Variable in MALTAB parallel for loop

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Ahmad Gad
Ahmad Gad el 20 de Nov. de 2017
Comentada: Ahmad Gad el 27 de Nov. de 2017
Hello all, I am having a code with the following construction. In this code, I need to extract K (M x M) from the parfor as this will save much time. Currently, I am working on it using ordinary for loop.
... % code
K = zeros(M,M);
parfor i = 1:N
k = ... % k is a matrix of dimensions (m x m) created in each pafor iteration.
u = ... % u is a vector of integers (n x 1) created in each pafor iteration.
K(u,u) = K(u,u) + k; % This line returns back an error message.
end
... % code
Is there anyway to re-write the code to be accepted in parfor loop without changing the calculation methodology. In a more general form, how can I involve a sliced reduction variable (K in this case) in parfor loop?
Thanks all and best Ahmad

Respuestas (2)

Jeff Miller
Jeff Miller el 20 de Nov. de 2017
Maybe something like this?
k = cell(N,1);
u = cell(N,1);
parfor i = 1:N
k{i} = ... % k is a matrix of dimensions (m x m) created in each pafor iteration.
u{i} = ... % u is a vector of integers (n x 1) created in each pafor iteration.
end
K = zeros(M,M);
for i = 1:N
K(u{i},u{i}) = K(u{i},u{i}) + k{i};
end
  1 comentario
Ahmad Gad
Ahmad Gad el 20 de Nov. de 2017
Hi Jeff, thanks for the answer.
I already isolated them in two different loops as you said. But my question was how to combine them all in a one parallel loop.
Thanks and best Ahmad

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Edric Ellis
Edric Ellis el 21 de Nov. de 2017
parfor doesn't support the notion of a variable that is both sliced and reduced. You need to recast things so that you have either a pure sliced or a pure reduced output. Here's one way that you might be able to achieve that - I'm not sure if I've completely understood your example, but perhaps this should give you sufficient information to continue:
m = 4;
n = 3;
K = zeros(m, m);
parfor idx = 1:n
% build 'k' and 'u' as per the example
k = idx .* ones(m, m);
u = (1:n)';
% Build an m-by-m increment
increment = zeros(m, m);
increment(u, u) = k(u, u);
% Ensure 'K' is a pure reduction variable
K = K + increment;
end
  1 comentario
Ahmad Gad
Ahmad Gad el 27 de Nov. de 2017
Hello Edric;
I had previously implemented a similar method, but for very big matrices (such as my cases), adding matrices many times always kills MATLAB. I am trying my best to avoid your final line
K = K + increment;
From my main example, M = 300k, N = 100k, m = n = 450
Thank you!

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