Borrar filtros
Borrar filtros

Why will one of my lines of this function not work?

1 visualización (últimos 30 días)
James Crowe
James Crowe el 21 de Nov. de 2017
Comentada: James Crowe el 21 de Nov. de 2017
How comes the line elseif p == 2 doesn't work when using the function in a script, but the rest do? Is there a better way to do this? Also how would I make it so that there is no output to the command window?
function [detA,trA] = myFunction(A,p)
if p == 1
detA = det(A);
elseif p == 2
trA = trace(A);
else
disp ('Invalid input')
end

Respuesta aceptada

Birdman
Birdman el 21 de Nov. de 2017
You define 2 outputs but in each if case, you only use one output and the other one is left unassigned. When you call function from workspace by not assigning its outputs, like
myFunction(A,1)
or
myFunction(A,2)
it automatically returns the first output. Since in the second if case you did not assign the first output to something, it does not return it. Instead try the following.
function y = myFunction(A,p)
if p == 1
y= det(A);
elseif p == 2
y= trace(A);
else
disp ('Invalid input')
end
and you can call it by
myFunction(A,1)
or
myFunction(A,2)

Más respuestas (0)

Categorías

Más información sobre Ordinary Differential Equations en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by