Closest value between two vectors

I have two vectors k and l.

     k             l
      1            5
      9            8
      12          32
      203        1003
      …          …

I want to find for each value in k, if the closest next value is in k or l (if its in k, add + 1 to a counter, if it’s l, add +1 to another counter. Any help would be imesnsly appreciated! Thanks a lot!

[KL]

you want to compare every element in k with k and l? if so, the next element in k and the current element in l? for the above example of yours, what should be the output?

[numnum]

Yes. compare very k element with k and l and find zhere the value closest and superior is, in k or l. The output should be for k(1)= 1, closest value > is l(1)=5. Countl=0+1 for k(2)= 9, closest value > is k(3)=12. Countk=0+1 for k(3)= 12, closest value > is l(3)=32. Countl=1+ 1 for k(4)= 203, closest value > is l(4)=1003. Countl=2+1

[KL]

I do not understand when you say ... closest value > is...

What does it mean?

...for k(2)= 9, closest value > is k(3)=12...

l(2) is 8, which is closer to 9 than 12.

and what happens to the last value of k? would you only compare it with l's last value (since there's no next element in k)?

[numnum]

the closest value that is superior. 8 < 9 so it would be rejected

[KL]

did you read my whole comment?

[numnum]

for the last value of k, z=we don't care about it.

Answer 1

[Andrei Bobrov]

kl =[1            5
9            8
12          32
203        1003];

z = randi([1 1003],8,1);

[~,ii] = min(abs(kl  - reshape(z,1,1,[])),[],2);
out = accumarray(ii(:),1);

for numel(K) ~= numel(L):

K = randi([-45 120],12,1);
L = randi([-15 300],18,1);
z = randi([-45 300], 8 ,1);

[~,ii] = min(abs([K(:);L(:)] - z(:)'));
adds = accumarray((ii(:) > numel(K)) + 1,1);

[numnum]

Thanks ! But k is a vector, and l is a seperate vector, and i want to co;pare the two together.

[Image Analyst]

Then just create kl.

kl = [k, l];

If k and l are different lengths, then please say so. Also say WHY you are wanting to do this.

[numnum]

Yes, but i want to keep information about whether the value comes from k or l. They are of differemt lengths, i should've mentionned that. Each value in an array represents the time at which an event happened. The goal is to find out the number of events that are consequentive in k vs the number of events that happen in k then in l.