why won't this code run?

[find(stock.permno)]==notrading(1);
for i=1:18522
end
for j=10137
newt=[find(toremove(i)==c)],:)=[];
end
for i=0:4
t((1+(i*126)):(126+(i*126)),:)=c((253+(i*378)):(379+(i*378)),:);
end
for i=1:5
trade(i).permno=top5(i,1);
for ii=0:4
trade(ii+1).price=d(1+(ii*252):252+(ii*252),4);
end

1 comentario

KSSV
KSSV el 23 de Nov. de 2017
How did you run? What error you got?

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 Respuesta aceptada

Bshara Murr
Bshara Murr el 23 de Nov. de 2017
Editada: Bshara Murr el 23 de Nov. de 2017

0 votos

Probably because you used the same local variable inside the main and nested loop. Try replacing the second i by a j (in every instance you are referring to it), and end your "for" loops.

Más respuestas (1)

Walter Roberson
Walter Roberson el 23 de Nov. de 2017

0 votos

You have
newt=[find(toremove(i)==c)],:)=[];
which attempts to do two assignments in one statement.

3 comentarios

LM
LM el 23 de Nov. de 2017
how should i split the assignments?
Walter Roberson
Walter Roberson el 23 de Nov. de 2017
Possibly you want
newt(find(toremove(i)==c),:)=[];
but it is difficult to be sure as your code does not mention newt anywhere else.
LM
LM el 23 de Nov. de 2017
got another error once i fixed it saying find has too many input arguments

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Preguntada:

LM
el 23 de Nov. de 2017

Comentada:

LM
el 23 de Nov. de 2017

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